SSC DAILY · QUANT
Top 25 Questions For SSC CGL, CHSL, CPO & Selection Phase 2026
A focused practice set on Averages — one of the most frequently tested Quant topics across SSC CGL, CHSL, CPO, and Selection Phase exams. Every question below includes a full step-by-step solution. Download the complete set as a PDF in English or Hindi to practice offline.
A note on sourcing: This set is built around Average-based question patterns that repeat frequently across SSC exams.
These questions are not verified as having appeared in any single specific year's paper — they're designed for practice and concept-building
based on recurring patterns commonly seen in SSC CGL, CHSL, MTS, and related exams.
1
A batsman has an average of 54 runs in 19 innings. How many runs should he score in the 20th innings to raise his average to 56?
A) 94 ✓
B) 84
C) 78
D) 54
Solution
Total runs in 19 innings = 54 x 19 = 1026. Required total after 20 innings = 56 x 20 = 1120. Runs needed in the 20th innings = 1120 - 1026 = 94.
2
The average age of a group of 24 students is 15 years. If a student aged 9 years leaves the group, what will be the new average age?
A) 10.26
B) 18.26
C) 15.26 ✓
D) 25.26
Solution
Total age = 15 x 24 = 360. After the student leaves: total = 360 - 9 = 351, students = 23. New average = 351 / 23 = 15.26 years.
3
The average age of a group of 8 people increases by 2 years when a person aged 14 is replaced by a new person. Find the age of the new person.
A) 30 ✓
B) 40
C) 50
D) 60
Solution
Increase in total age = 2 x 8 = 16. New person's age = old age + increase = 14 + 16 = 30.
4
The average of 5 numbers is 72. The average of the first three is 70, and the last three is 75. What is the third number?
A) 65
B) 75 ✓
C) 85
D) 95
Solution
Sum of first three = 70 x 3 = 210. Sum of last three = 75 x 3 = 225. Sum of all five = 72 x 5 = 360. The third number is counted in both groups, so: 210 + 225 - 360 = 75.
5
The average marks of 30 students are 72. The top 5 students scored an average of 86 marks, while the last 5 students averaged 54. What is the average of the remaining 20 students?
A) 72
B) 73 ✓
C) 83
D) 84
Solution
Total marks = 72 x 30 = 2160. Top 5 total = 86 x 5 = 430. Last 5 total = 54 x 5 = 270. Remaining 20 total = 2160 - 430 - 270 = 1460. Average = 1460 / 20 = 73.
6
The average of 6 numbers is 45. The average of the first four numbers is 40, and the fifth number is 50. What is the sixth number?
A) 65
B) 70
C) 60 ✓
D) 80
Solution
Total of 6 numbers = 45 x 6 = 270. First four total = 40 x 4 = 160. Fifth = 50. Sixth number = 270 - 160 - 50 = 60.
7
Average of five consecutive even numbers is 76. What is the largest of these numbers?
A) 78
B) 68
C) 58
D) 80 ✓
Solution
For 5 consecutive even numbers, the average equals the middle (3rd) number, which is 76. The largest number = 76 + 4 = 80.
8
A cricketer has an average of 30 runs in 9 innings. In the 10th inning, he scores some runs, and his average increases to 31 runs. How many runs did he score in the 10th inning?
A) 25
B) 30
C) 35
D) 40 ✓
Solution
Total in 9 innings = 30 x 9 = 270. Total in 10 innings = 31 x 10 = 310. Runs in the 10th inning = 310 - 270 = 40.
9
The average age of 5 friends is 24 years. If two new friends join the group, with one aged 25 years and another aged 30 years, what will be the new average age of the expanded group?
A) 24 years
B) 24.5 years
C) 25 years ✓
D) 25.5 years
Solution
Total age of 5 friends = 24 x 5 = 120. Adding two friends aged 25 and 30: new total = 120 + 55 = 175, count = 7. New average = 175 / 7 = 25.
10
The average weight of 10 students was calculated as 50 kg. Later, it was discovered that one student's weight was wrongly read as 40 kg instead of 60 kg. What is the correct average weight?
A) 51 kg
B) 52 kg ✓
C) 48 kg
D) 50.5 kg
Solution
Original total (with error) = 50 x 10 = 500. The weight was under-recorded by 60 - 40 = 20 kg. Correct total = 500 + 20 = 520. Correct average = 520 / 10 = 52.
11
40% of the employees in a factory are workers. All the remaining employees are executives. The annual income of each worker is Rs. 390. The annual income of each executive is Rs. 420. What is the average annual income of all the employees in the factory together?
A) 365
B) 520
C) 306
D) 408 ✓
Solution
40% workers earn Rs. 390, 60% executives earn Rs. 420. Average = 0.40 x 390 + 0.60 x 420 = 156 + 252 = 408.
12
The average of three numbers A, B, and C is 48. The average of A and B is 45. The average of B and C is 49. What is the value of B?
A) 42
B) 44 ✓
C) 46
D) 48
Solution
Sum(A,B,C) = 48 x 3 = 144. Sum(A,B) = 45 x 2 = 90. Sum(B,C) = 49 x 2 = 98. Adding these: Sum(A,B) + Sum(B,C) = (A+B+C) + B = 144 + B = 90 + 98 = 188. So B = 44.
13
The average age of 5 members of a family is 20 years. If a new member joins the family, the average age becomes 18. What is the age of the new member?
A) 10 years
B) 12 years
C) 8 years ✓
D) 15 years
Solution
Total age of 5 members = 20 x 5 = 100. After the new member joins: total = 18 x 6 = 108. New member's age = 108 - 100 = 8.
14
Find the average of the first n odd natural numbers.
A) n ✓
B) 2n
C) n/2
D) 3n+1
Solution
The sum of the first n odd natural numbers is always n squared (n^2). So the average = n^2 / n = n.
15
What is the average of all three-digit numbers divisible by 23?
A) 752
B) 552 ✓
C) 652
D) 452
Solution
Three-digit multiples of 23 range from 115 (23 x 5) to 989 (23 x 43), forming an arithmetic sequence. The average of an AP equals (first + last) / 2 = (115 + 989) / 2 = 552.
16
The average age of 40 students in a class is 16 years. When a new student is admitted, the average increases by 0.2 years. What is the age of the new student?
A) 24.2 ✓
B) 20.2
C) 19.2
D) 16.2
Solution
Total age of 40 students = 16 x 40 = 640. New total with 41 students = 16.2 x 41 = 664.2. New student's age = 664.2 - 640 = 24.2.
17
The monthly average salary for 8 employees plus one supervisor is Rs. 15,000. If the supervisor earns Rs. 25,000, what is the average salary of the 8 employees?
A) Rs. 14,750
B) Rs. 13,000
C) Rs. 13,750 ✓
D) Rs. 13,500
Solution
Total salary of 9 people = 15000 x 9 = 135000. Subtracting the supervisor's salary: 135000 - 25000 = 110000. Average of 8 employees = 110000 / 8 = 13750.
18
A company has 80 employees, of whom 35% are women. The average monthly salary of the women is Rs. 72,000, while that of the men is Rs. 68,000. What is the overall average monthly salary (in Rs. 000) of the whole workforce?
A) 70.8
B) 699.4
C) 245.4
D) 69.4 ✓
Solution
Women = 35% of 80 = 28, Men = 52. Total salary = 28 x 72000 + 52 x 68000 = 5,552,000. Average = 5,552,000 / 80 = 69,400, i.e. 69.4 (in Rs. 000).
19
Three numbers are such that when the average of any two of them is added to the third, the results obtained are 180, 168, and 150, respectively. What is the average of the original three numbers?
A) 83 ✓
B) 84
C) 85
D) 86
Solution
Let the numbers be a, b, c. The three conditions give: a+b+2c=360, 2a+b+c=336, a+2b+c=300. Adding all three: 4(a+b+c) = 996, so a+b+c = 249. Average = 249 / 3 = 83.
20
The average salary of 24 employees is Rs. 40,000. The average salary of 8 senior staff is Rs. 60,000. What is the average salary for the other employees?
A) Rs. 30,000 ✓
B) Rs. 40,000
C) Rs. 50,000
D) Rs. 60,000
Solution
Total salary of 24 employees = 40000 x 24 = 960000. Total of 8 senior staff = 60000 x 8 = 480000. Remaining 16 employees' total = 960000 - 480000 = 480000. Average = 480000 / 16 = 30000.
21
A cricketer's average in 10 innings is 58. If his highest score is excluded, the average drops to 54. What is his highest score?
A) 93
B) 92
C) 94 ✓
D) 95
Solution
Total of 10 innings = 58 x 10 = 580. Total of 9 innings (excluding highest) = 54 x 9 = 486. Highest score = 580 - 486 = 94.
22
A batsman's average score for a certain number of innings is 44. If he scores 132 runs in the next innings, his average becomes 48. How many innings did he play earlier?
A) 21 ✓
B) 22
C) 23
D) 24
Solution
Let n = number of innings played earlier. 44n + 132 = 48(n+1). So 44n + 132 = 48n + 48, giving 84 = 4n, so n = 21.
23
The average of 13 numbers is 70. The average of the first five numbers is 60. The average of the next five numbers is 25% higher than the average of the first five numbers. The 11th number is 6 less than the 13th number, and the 12th number is 4 greater than the 13th number. What is the average of the 11th and 12th numbers?
A) 78 ✓
B) 77
C) 76
D) 74
Solution
Total of 13 numbers = 70 x 13 = 910. First five total = 60 x 5 = 300. Next five average = 60 x 1.25 = 75, total = 375. First ten total = 300 + 375 = 675. Remaining three (11th, 12th, 13th) total = 910 - 675 = 235. Let 13th = x, so 11th = x-6, 12th = x+4. Sum = 3x - 2 = 235, so x = 79. So 11th = 73, 12th = 83. Average of 11th and 12th = (73+83)/2 = 78.
24
Three groups of students have average ages 18, 20, and 22 respectively. If the number of students in the three groups is in the ratio 2:3:5, what is the overall average age?
A) 19.6
B) 20.6 ✓
C) 15.6
D) 14.6
Solution
Using the ratio 2:3:5, let the counts be 2k, 3k, 5k. Weighted total = 2k(18) + 3k(20) + 5k(22) = 206k. Total students = 10k. Average = 206k / 10k = 20.6.
25
The average of 11 numbers is 68. If the average of the first five is 63 and the average of the last five is 72, find the 6th number.
A) 73 ✓
B) 74
C) 75
D) 76
Solution
Total of 11 numbers = 68 x 11 = 748. First five total = 63 x 5 = 315. Last five total = 72 x 5 = 360. The 6th number (the only one not in either group) = 748 - 315 - 360 = 73.
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